The air in a bicycle tire is bubbled through water and collected
The correct answer is p=KH× bar=×103 bar×mol of O2mol of =×103 ×mol of O21000=×nO2×18⇒nO2=×10−3⇒mmol of O2=1
2} ) is bubbled through water at ( 293 mathrm if o2 gas is bubbled through water at 303k The correct answer is p=KH× bar=×103 bar×mol of O2mol of =×103 ×mol of O21000=×nO2×18⇒nO2=×10−3⇒mmol of O2=1 ifa cfl pKHx 09204682103 barmolofO2molofH2O 09204682103molofO2100018 0920468218nO2 0920468218nO2 109103n02 mmolofO21millimole
if o2 gas is bubbled through water at 303k O2 in water is too small , nearly negligible ) [ JEE Main
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